b = 6 – 3a
b = 6 – 3()
b = 6 –
b =
Substitusikan a = b = ke (1)
a + b + c = 1
+ c = 1
3 + c = 1
c = 1 – 3
c = –2
b = 6 – 3a
b = 6 – 3()
b = 6 –
b =
Substitusikan a = b = ke (1)
a + b + c = 1
+ c = 1
3 + c = 1
c = 1 – 3
c = –2
Editor: Ahmad Latief Fahrezi